Implementation to calculate an estimate of the number π (Pi).
We take a random point P with coordinates (x, y) such that 0 ≤ x ≤ 1 and 0 ≤ y ≤ 1. If x² + y² ≤ 1, then the point is inside the quarter disk of radius 1, otherwise the point is outside. We know that the probability of the point being inside the quarter disk is equal to π/4 double approx(vector<Point> &pts) which will use the points pts (drawn at random) to return an estimate of the number π
- Note
- This implementation is better than naive recursive or iterative approach.
- Author
- Qannaf AL-SAHMI